Question

a car cost 240000 its value depreciates at the rate of 5% every year. if after some time period, its value is₹ 205770 find the time period.

Answer 1

Answer:

3 years

Step-by-step explanation:

We solve this depreciation problem using the formula

$A = P(1 - \frac{R}{100} )^{n}$

Where

A = Final value

P = Initial value

n = Time duration

So,

$205770 = 240000(1 - \frac{5}{100} )^{n}$

$\frac{205770}{240000} = 0.95^{n}$

0.857 = $0.95^{n}$

Take logarithms of both sides

log0.857 = log $0.95^{n}$

log0.857=nlog0.95

n = log0.857/log0.95

n = 3

∴ Time duration is 3 years

Answer 2

Answer:

3 years

Step-by-step explanation:

the upper anser is correct