a car covers 20 km with a speed of 10 km per hr and next 40 km with a speed of 20 km per hour and next 100 km in 2 hrs. Calculate the average speed.Plzz give the answer.
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Speed 1 = 10km/h
distance 1 = 20km
Time taken (t1) = distance/ time = 20/10 = 2 hr.
Distance 2 = 40km
speed 2 = 20km/h
t2 = 40/ 20 = 2 hr.
Distance 3 = 100km
t3 = 2hr.
Average speed = total distance/ total time taken
= (20 + 40 + 100)/ (3+2+2)
= 160/6
= 26.6
Therefore,
average velocity here would be 26.6 km/h.
distance 1 = 20km
Time taken (t1) = distance/ time = 20/10 = 2 hr.
Distance 2 = 40km
speed 2 = 20km/h
t2 = 40/ 20 = 2 hr.
Distance 3 = 100km
t3 = 2hr.
Average speed = total distance/ total time taken
= (20 + 40 + 100)/ (3+2+2)
= 160/6
= 26.6
Therefore,
average velocity here would be 26.6 km/h.
Pranav20021:
t1 is wrong 20/10= 2
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