A car covers 50km at a uniform velocity of 45km/h and the next 50km in 90km/h.find the average velocity of car
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av v of the car is =fatal distance / tatal time
speed = 45&90km/hr
time = distance /time
t1 = 50/45
t1= 10/9
t2 = 50/90
t2= 5/9
av v is 50+50/(10/9+5/9)
av v is 100/15/9
av v is o.74074
speed = 45&90km/hr
time = distance /time
t1 = 50/45
t1= 10/9
t2 = 50/90
t2= 5/9
av v is 50+50/(10/9+5/9)
av v is 100/15/9
av v is o.74074
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