Consider the linear equation x+3y=4 write another linear equation in two variables such that the geometric representation of the pair so formed is (i) intersecting lines (ii) parallel lines (iii) coincident lines
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(i)
The given line is x + 3y = 4
So, any intersecting line be x + y = 2
Thus, x + 3y = 4 and x + y = 2 are pair of intersecting lines, and they intersect each other at (1, 1).
(ii)
The given line is x + 3y = 4
So, any parallel line be x + 3y = 6
Thus, x + 3y = 4 and x + 3y = 6 are pair of parallel lines.
(iii)
The given line is x + 3y = 4
So, any coincident line be 2x + 6y = 8
Thus, x + 3y = 4 and 2x + 6y = 8 are pair of coincident lines.
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(i)
The given line is x + 3y = 4
So, any intersecting line be x + y = 2
Thus, x + 3y = 4 and x + y = 2 are pair of intersecting lines, and they intersect each other at (1, 1).
(ii)
The given line is x + 3y = 4
So, any parallel line be x + 3y = 6
Thus, x + 3y = 4 and x + 3y = 6 are pair of parallel lines.
(iii)
The given line is x + 3y = 4
So, any coincident line be 2x + 6y = 8
Thus, x + 3y = 4 and 2x + 6y = 8 are pair of coincident lines.
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