Question

A car covers a distance of 250 m in 6 seconds. If the
acceleration of the car is 6 ms 2. Find the final velocity of
the car.​

Answer 1

GIVEN:

s = 250m

t = 6sec

a = 6m/s²

v = ?

FORMULA USED:

● s = ut + ½at²

250 = 6u + ½×6×6×6

250 = 6u + 108

6u = 250 - 108

6u = 142

u = 142/6

● v = u + at

v = 142/6 + 6×6

v = 142/6 + 36

v = (142 + 216) ÷ 6

v = 358÷6

v = 59.66 m/s²

Answer 2

Answer:

V = 54.772 m/s

Explanation:

distance = 250 m

time = 6 s

Acceleration = 6m/s ²

V = ?

Finding final velocity:

V² - U² = 2as

V² - (0) ² = 2 × 6 × 250

V² = 3000

V = root 3000

V = 54.772 m/s²

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