Question

a car covers first 50 km at a uniform velocity of 45 kilometre per hour and the next 50 kilometre at 90 kilometre per hour find the average velocity of the car

Answer 1

The initial velocity of the car (u)= 45km/hr
The final velocity of the car (v)= 90km/hr
Average velocity = u+v/2
= 45 +90 / 2
= 135 / 2
= 67.5 km/hr

Answer 2

Answer:

The average velocity of the car is 50 km/hr.

Explanation:

First the car covers 50 km at the uniform speed 45 km/hr

And the next 50 km at thr speed of 90 km/hr

Average velocity =(V₁X₁ +V₂X₂)/(V₁+V₂) Where,V₁= Velocity in first position, X₁= First cover distance ,V₂=Velocity in second position, X₂=second cover distance.

Here,V₁= 45 km/hr,X₁= 50Km ,V₂= 90 km/hr,X₂=50 km

So,Average velocity = {(45x50)+(90x50)}/(45+90) = 6750/135= 50 km/hr

The average velocity of the car is 50 km/hr.