the diagonals of a rhombus ABCD intersect at O,AO 3cm,BO 4cm then,length of BC is ____
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Answered by
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as we know that the diagonals of rhombus bisect each other at right angles.
by pathagorian triplet,
BC^2=AO^2+BO^2
BC=√3^2+4^2
=√9+16
=√25
=5
by pathagorian triplet,
BC^2=AO^2+BO^2
BC=√3^2+4^2
=√9+16
=√25
=5
satyam19906pagl3t:
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5
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