Question

A car falls from a ledge and reach the ground at 5 second what is the height of ledge by what speed it will fall on the ground

Answer 1

Final velocity of the car will be 0

And let initial velocity be u, then

From v = u +at

v = u +gt

0 = u - 9.8*5 as time = 5s

u = 49 m/s

S = ut - 1/2 gt^2

S = 122.5 m

Answer 2

g=9.8

t=5s

v=0

v=u+gt

0=u+9.8×5

0=u+49

u=49m/s

h=ut+1/2gtsquare

h=245+1/2×9.8×5

245+24.5

h=269.5