A car falls off a ledge and drops to ground in 0.5s let g= 10m/s . Find the speed on striking the ground. What is its average speed during 0.5s ?
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Answer:
Given,
time taken=0.5s
g=10ms
−2
As the car is under free fall, the initial speed is zero.
(a) Under free fall,
u=0
a=g
v=u+at
v=0+10×0.5
v=5ms
−1
(b) Average speed =
2
u+v
=
2
0+5
=2.5ms
−1
(c) From newton's equation of motion, As u=0,
h=ut+
2
1
gt
2
When h is the height, t is the time of free fall, g is the acceleration due to gravity. Putting the values in the above equation, we get
h=
2
1
×10×(0.5)
2
=5×0.25=1.25m
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