A car falls off a ledge and drops to the ground in 0.5s.(Take g=10m/ssquare).Find the speed of the car on striking the ground.Find the average speed of the car in 0.5s. Find the height of the ledge from the ground.
Answers
Answered by
14
v=u+at
u is 0
v=10x0.5
v=5m/s
s=ut+0.5(at^2)
s=0+0.5(10x0.25)
s=1.25m
u is 0
v=10x0.5
v=5m/s
s=ut+0.5(at^2)
s=0+0.5(10x0.25)
s=1.25m
Answered by
28
Given :
Here, u = 0
t = 0.5s
and a= g = + 10 m/s²
i) Final speed of car when striking the ground :
v = u + at
= 0 + gt
= 10 × 0.5
= 5 m/s
ii) Average speed :
Vₐ = u + v/2
= 0 + 5/2
= 2.5 m/s
iii) Height of the ledge = total distance covered by car
h = 1/2gt²
= 1/2 × 10 × ( 0.5)²
= 1.25m
ATLAST , FINAL ANSWERS WE GET :
i ) 5 m/s
ii) 2.5 m/s
iii) 1.25m
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