A car from rest accelerate with constant speed of 2m/s^2 . Calculate the distance travelled in 8 secs
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Answer to your question is 64 m
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Answered by
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Heya mate,
Here is your answer,. ⬇️ ⬇️
_________
Here,
Acceleration (a) = 2 m/s^2
Initial velocity(u) = 0 m/s
Time(t) = 8 secs.
Distance (s) =?
Now, by using formulae,
s = ut + 1/2 * a * t^2
Or, s = 0 * 8 + 1/2 * 2 * 8^2
Or, s = 8^2 = 64.
➡️ Hence, the car travelled 64 m.
_________
Hope this helps,.
If helps, please mark 'thanks' ^_^
_________
REGARDS, ARNAB ✌️
THANK YOU
Here is your answer,. ⬇️ ⬇️
_________
Here,
Acceleration (a) = 2 m/s^2
Initial velocity(u) = 0 m/s
Time(t) = 8 secs.
Distance (s) =?
Now, by using formulae,
s = ut + 1/2 * a * t^2
Or, s = 0 * 8 + 1/2 * 2 * 8^2
Or, s = 8^2 = 64.
➡️ Hence, the car travelled 64 m.
_________
Hope this helps,.
If helps, please mark 'thanks' ^_^
_________
REGARDS, ARNAB ✌️
THANK YOU
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