Question

a car from rest and pick up a velocity of 54m/h in ten seconds. calculate the acceleration of the car?
pls ans asap no spams ​

Answer 1

◑Answer :-

1.5 m/s²

◑Given :-

• Car from rest (Initial velocity = 0)
• Final velocity = 54km/hr
• time taken = 10 seconds

i.e

• u = 0
• v = 54 km/hr
• t = 10 seconds

◑To find :-

• Acceleration of the body

◑Solution:-

Acceleration is defined as change in velocity per unit time is called acceleration thus according to definition,

Acceleration = Change in velocity/Time

A = final velocity- Initial velocity/ Time

a = v- u/t

As the final velocity is 54km/hr Lets convert into m/s

1km/hr = 5/18 m/s

54 km/hr = 54 × 5/18

= 3× 5

= 15 m/s

So,

54km/hr = 15m/s

So,

• Final velocity (v) = 15m/s
• Initial velocity(u) = 0m/s
• Time(t) = 10 sec

Substituting the values,

a = v- u/t

a = 15-0/10

a = 15/10

a = 1.5 m/s²

◑So, acceleration of the body is 1.5m/s²

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Know more some formulae:-

• v = u + at
• s = ut + ½at²
• v² - u² = 2as
• u = v-at
• s = vt-½at²
• a = F/M

where,

v = Final velocity

u = Initial velocity

s = Distance covered

a = acceleration

F = force

M = mass of the body

Answer 2

Answer:

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