Question

A car goes 6m in North in 2s and 8m in East in 2s . calculate the total distance it cover in 4 second

Answer 1

Answer:

14 m

Explanation:

As per the provided information in the given question, we have :

• A car goes 6m in North in 2s and 8m in East in 2s.

We have been asked to calculate the total distance it covers in 4 seconds.

Firstly, it covers 6m in 2s and then it covers 8m in 2s. Hence, total time will be (2s + 2s) which is equal to 4s.

Now, the total distance covered in 4s will be the sum of the distance covered in first 2 seconds and the distance covered in next 2 seconds. Mathematically,

→ Total distance = Distance covered in first 2s + Distance covered in next 2s

→ Total distance = 6m + 8m

→ Total distance = 14 m

Therefore, the total distance it covers in 4 seconds is 14 m.

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Learn More :

• Distance is the total length of the path covered by the body.
• It is a scalar quantity i.e, it has only magnitude but not direction.
• SI unit of distance is 'metre (m)'.
• It is denoted by 's'.
• Distance = Speed × Time

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Answer 2

Given :

• A car goes 6 m in North in 2s .
• Than it goes 8 m in East in next 2s .

To Find :

• Total Distance Covered = ?

Solution :

$\dag \; {\underline{\pmb{\frak{ \; First \; Case \; :- }}}}$

• Goes to North = ${\sf{ D_1 }}$ = 6 m
• Time Taken = ${\sf{ T_1 }}$ = 2s

$\dag \; {\underline{\pmb{\frak{ \; Second \; Case \; :- }}}}$

• Goes to east = ${\sf{ D_2 }}$ = 8 m
• Time Taken = ${\sf{ T_2 }}$ = 2s

$\\ \qquad{\rule{150pt}{1pt}}$

$\dag \; {\underline{\pmb{\frak{ \; Calcuting \; the \; Total \; Distance \; :- }}}}$

$\begin{gathered} \; \longmapsto \; \; \sf { Total \; Distance = D_1 + D_2 } \\ \end{gathered}$

$\begin{gathered} \; \longmapsto \; \; \sf { Total \; Distance = 6 \; m + 8 \; m } \\ \end{gathered}$

$\begin{gathered} \; \longmapsto \; \; {\qquad{\red{\sf { Total \; Distance \; Covered = 14 \; m }}}} \\ \end{gathered}$

$\\ \qquad{\rule{150pt}{1pt}}$

$\dag \; {\underline{\pmb{\frak{ \; Therefore \; :- }}}}$

❛❛ Total Distance Covered by the car is 14 m . ❜❜

$\\ {\underline{\rule{300pt}{9pt}}}$