A car goes from speed of 270m/s to 310m/s in 1min.what is it acceleration
Answers
Provided that:
- Initial velocity = 270 mps
- Final velocity = 310 mps
- Time = 1 minute
To calculate:
- Acceleration
Solution:
- Acceleration = 0.6 mps sq.
Using concepts:
- We can use either first equation of motion or acceleration formula to solve this question.
- Formula to convert minutes into seconds as SI unit of time is seconds.
Using formulas:
• Acceleration formula:
- a = (v-u)/t
• First equation of motion:
- v = u + at
• Formula to convert min-sec:
- 1 min = 60 seconds
Required solution:
~ Firstly let us convert minutes into seconds by using suitable formula!
→ 1 min = 60 seconds
- Henceforth, converted!
~ Now let us find out the acceleration by using suitable formula!
By using acceleration formula...
→ a = (v-u)/t
→ a = (310-270)/60
→ a = 40/60
→ a = 4/6
→ a = 2/3
→ a = 0.6 mps sq.
→ Acceleration = 0.6 mps sq.
By using first equation of motion...
→ v = u + at
→ 310 = 270 + a(60)
→ 310 - 270 = 60a
→ a = 40/60
→ a = 4/6
→ a = 2/3
→ a = 0.6 mps sq.
→ Acceleration = 0.6 mps sq.
Additional information:
Question :-
- A car goes from speed of 270 m/s to 310 m/s in 1 min . What is it Acceleration .
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Answer :-
- Acceleration = 0.6 m/s² .
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Explanation :-
- Here, Initial Velocity is 270 m/s , Final Velocity is 310 m/s and Time is 1 min [ 60 sec ] . We have to calculate the Acceleration .
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◆ Formula Required :-
- ᴀ = [ v - u ] / ᴛ
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◆ Here ,
- ᴀ denotes to Acceleration .
- v denotes to Final Velocity .
- u denotes to Initial Velocity .
- ᴛ denotes to Time .
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∴ By substituting the given values :-
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Hence :-
- Acceleration = 0.6 m/s² .
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