Question

A car has a velocity of 10 ms -1 . It
accelerates at 0.2 ms- 2 for half
minute. Find the distance
travelled during this time and
the final velocity of the car.
(390 m, 16 ms -1)​

Answer 1

v² = u² + 2as

16² = 10² + 2.16.s

256 = 100 + 32s

256-100 = 32s

156 = 32s

156/32 = S

4.8 m

.

..

...

...10 thanx + follow = INBOX

Answer 2

Explanation:

initial velocity=10m/s

acc=0.2m/s²

time =30sec

s=ut+1/2at²

s=10×30+1/2×0.2×900

s=300+90

s=390 m

v²-u²=2as

v²-100=156

v²=256

v=16