Question

Find the roots of the quadratic equation 3x^2 - 2root6x + 2= 0 by factorisation.​

Answer 1

We have here,

3x²-2√6x+2=0

Multiplying x² coefficient and constant term we get 6

Splitting 6 in the terms of the middle term

By splitting the middle term,

→3x²-√6x-√6x+2=0

→√3x(√3x-√2)-√2(√3x-√2)=0

→(√3x-2)²

→√3x-√2=0

→x = √2/√3

The roots of the equation are √2/√3 and √2/√3