Question

a car has constant acceleration of 10m/s^2. How much distance the car has covered after 10s of time​

Answer 1

Answer:

Correct option is

A

200 m

Given: 

Initial velocity is: u=0

Acceleration is: a=4 ms2

Time is: t=10 s

Using second equation of motion:

s=ut+21at2

s=0×10+21×4×102

   =0+200=200 m

Answer 2

Answer:

Given that

The car is initially at rest;

initial velocity (u) = 0 ms-1

Acceleration (a) = 4 ms-2

Time period (t) = 10 s

Find out

What distance will it cover in 10 s after start

Formula

As per the second motion equation, s = ut+1/2 at2

Therefore, the total distance covered by the car (s) = 0 * 10m + 1/2 (4ms-2)(10s)2

= 200 meters