Question

A car has initial velocity of 72 km/hr. it is accelerated at 2ms-2. find the final velocity and distance covered after 3 sec.

Answer 1

u=72 km/hr
a=2m/s2
t=3 sec
v=u+at
=72+2(3)
=72+6
=78 km/hr

Answer 2

Hi there!

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Given :

Initial velocity (u) = 72 km/h = 20m/s.

Acceleration (a) = 2m/s².

Time taken (t) = 3 sec.

To find :

Final velocity (v) = ?

Distance covered (s) =?


Solution :

We will use first equation of motion here;

v = u + at

⇒ v = 20 + 2 × 3

⇒ v = 20 + 6

⇒ v = 26 m/s.

Hence,

The final velocity is 26 m/s.

Now,

We will use third equation of motion ;

S = ut + 1 / 2 at²

S = 20 * 3 + 1 / 2 * 2 * 3 * 3

S = 60 + 9

S = 69 m.

Hence,

The distance travelled is 69m.

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Thanks for the question !

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