Question

A car having good tyres moves on a dry road with a constant deceleration of 4.28 m/s. If the car initia ly travels with 20 m/s then calculate how long does a car take

to stop?​

Answer 1

Answer:

Answer

Since, the accleration is constant and decreasing the speed, a=−4.92m/s

2

Initial velocity, v

0

=24.6m/s

Final velocity, v

f

=0m/s

Then,

v

f

=v

0

+at

⇒t=

a

v

f

−v

0

=

−4.92m/s

2

0−24.6m/s

⇒t=5.00s

Thus, car stops after 5.00s. ok thanks