A car having mass 700 kg is moving at a speed of 90 kilometre per hour on applied brake it speed is required to 36 km per hour in 10 second calculate the force applied by the break
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m=mass, u=initial velocity, v=final velocity, t=time, a=acceleration, F=force
m=700kg
u=90km/h
v=36km/h
t=10s
a=v-u/t
=36-90/10
=-54/10
a=-5.4km/h²=-19.44m/s²
F=ma
=700×-19.44
F =-13608N
So, the force applied by breaks = -13608
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