Question

A car having mass
7oo kg increases its velocity from 14 km / h to 50 km/h in 35 seconds. what is constant force applied?​

Answer 1

Answer:

Explanation:

14km/h= (14×1000)m/(1×3600)s= 35m/9s

50km/h= (50×1000)m/(1×3600)s= 125m/9s

Initial velocity,U= (35/9)ms⁻¹

Final velocity,V= (125/9)ms⁻¹

time,t=35s

acceleration,a = (V-U)/t

                        = [(125/9)ms⁻¹ - (35/9)ms⁻¹]/35s

                        =[(90/9)ms⁻¹]/35s

                        = (10ms⁻¹)/35s

                       a = (2/7)ms⁻²

Force,F=m×a

            = 700kg × (2/7)ms⁻²

          F  = 200 N

Answer 2

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