A car increases its speed from 20 km/h to 30 km/h in 10 seconds. its acceleration is a) 30 m/s b) 3 m/s c) 18 m/s d) 0.83 m/s calculate
Answers
Answered by
97
"Ans: Acceleration = Change in velocity / time taken
ACCELERATION = (V - U)/ T
Then
Initial velocity level = 20 KM/HR
Final velocity level= 30 KM/ HR
ACCELERATION = (30 - 20) KM/HR
= 30 KM/HR SQUARE = 2.777 m/s
Time = 10 seconds
Acceleration = 2.77 m/10s*s
Acceleration = 0.28 m/s^2
Here is the solutions."
Answered by
72
Unit of Acceleration is m/s^2.
a= (v2-v1)/(t2-t1)
(t2-t1)=10 sec
v2= 30 km/h = 30×5/18 = 8.33 m/s
v1= 20km/h = 20×5/18= 5.55 m/s
a= (8.33-5.55)/10 = 2.77 /10
a= 0.277m /s^2
a= 0.28 m/s^2
a= (v2-v1)/(t2-t1)
(t2-t1)=10 sec
v2= 30 km/h = 30×5/18 = 8.33 m/s
v1= 20km/h = 20×5/18= 5.55 m/s
a= (8.33-5.55)/10 = 2.77 /10
a= 0.277m /s^2
a= 0.28 m/s^2
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