a car increases its speed from 20 km/h to 50km/h in 10 sec what is its acceleration
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Final velocity, v = 50 km/h
Initial velocity, u = 20 km/h
Time taken, t = 10 sec
So the change in velocity can be calculated as
v−u=(50−20)km/hr
= 30 km/hr
On converting the units into m/s
We get,
= 30 km/hr ⇒30×1000/60×60⇒253 m/s
We know the acceleration formula,
a=(v−u)/t
Put the value of change in velocity and time in above formula
we get,
=25/3×1/10
=5/6 m/s²
Answered by
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Answer:
3m/s^2
Explanation:
initial velocity(u)=20m/s
final velocity(v)=50m/s
time(t)=10s
therefore,
a=(v-u)/t=(50-20)/10=30/10=3m/s^2
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