Question

A car increases its speed from 36 km/hr to 72 km/hr in 10s. Find acceleration

Answer 1

Hey mate!!!!!!


First convert the km/hr speed to m/s
For this we multiply the number with 5/18


so we have
36km/hr = 36 × 5/18 = 10m/s
72km/hr = 72 × 5/18 = 20m/s

now we know that
$a = \frac{v - u}{t}$
where a is the acceleration, v is final velocity, u is initial velocity and t is the time.


So
$a = \frac{20 - 10}{10} \\ a = \frac{10}{10} \\ a = 1 \\ so \: acceleration \: is \: 1m {s}^{ - 2}$
so acceleration is 1m s^-2 or
1m/s^2


Hope it helps dear friend ☺️✌️✌️

Answer 2

HEY USER !!

HERE'S UR ANSWER ----

Given ,,

u = 36km/hr

= 36 × 5/18 m/s

= 10 m/s

v = 72 km/hr

= 72 × 5/18 m/s

= 20 m/s

We know that , acceleration(a) = v - u / t

= 20 - 10 / 10

= 10/10

= 1 m/s^2