A car initially at set picks up a velocity of 72km/hr in 1/4mins.....Find the acceleration and the total distance covered
Answers
Answered by
1
72km/hr=20m/s
1/4min=15 sec
v=u+at
20=a×15
a=4/3 m/s
s=ut+1/2 at^2
=1/2×4/3×225
=90m
1/4min=15 sec
v=u+at
20=a×15
a=4/3 m/s
s=ut+1/2 at^2
=1/2×4/3×225
=90m
Anonymous:
did you got it
Answered by
0
u=0m/s
v=72km/hr=72/1×5/18=20m/s
s=25m
By third equation of motion
v^2-u^2=2as
a=v^2-u^2/2s
a=400-0/2×25
a=400/50
a=8m/s^2
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