A car is accelerated uniformly from 36 km per hour to 90 km per hour in 3 seconds. Calculate: (a) The acceleration of car (b)The distance covered by the car in that time
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Explanation:
(a)acceleration(a)=change in velocity/time
=90-36/3
=54/3
=18m/s^2
(b). distance=?
s=ut+1/2at^2
s=36*3+1/2*18*3*3
=108+9*9
=108+81
=189m
distance=189m
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