A car is being driven by a force of 2.5 ×10^10 N.Travelling at a constant speed of 5 m/s ,it takes 2 minutes to reach a certain place . Calculate the work done....
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Answered by
13
Work done = Force * Displacement or (sometimes distance traveled )
Given, Force = 2.5*10^10,
Speed = 5m/s,
Time = 2min = 120 sec,
Distance traveled = 5*120 = 600m,
Now work done = 2.5*10^10 * 600,
=>1500*10^10,
Hope you understand !
Given, Force = 2.5*10^10,
Speed = 5m/s,
Time = 2min = 120 sec,
Distance traveled = 5*120 = 600m,
Now work done = 2.5*10^10 * 600,
=>1500*10^10,
Hope you understand !
TANU81:
Wrg
Answered by
17
Hey there!
Given,
Speed, v = 5 m/s
Force,
![F = 2.5 \times {10}^{10} F = 2.5 \times {10}^{10}](https://tex.z-dn.net/?f=F+%3D+2.5+%5Ctimes++%7B10%7D%5E%7B10%7D+)
Time, t = 2min = 120 sec
Distance covered, d= 5 m/s × 120s
= 600m
Workdone = Force × Distance
W = F × d
![= 2.5 \times {10}^{10} \times 600 = 2.5 \times {10}^{10} \times 600](https://tex.z-dn.net/?f=+%3D+2.5+%5Ctimes++%7B10%7D%5E%7B10%7D++%5Ctimes+600)
![= 1500 \times {10}^{10} = 1500 \times {10}^{10}](https://tex.z-dn.net/?f=+%3D+1500+%5Ctimes++%7B10%7D%5E%7B10%7D+)
![= 15 \times {10}^{12} = 15 \times {10}^{12}](https://tex.z-dn.net/?f=+%3D+15+%5Ctimes++%7B10%7D%5E%7B12%7D+)
Hence,
Workdone = 15 × 10¹² Joules
HOPE IT HELPED ^_^
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Given,
Speed, v = 5 m/s
Force,
Time, t = 2min = 120 sec
Distance covered, d= 5 m/s × 120s
= 600m
Workdone = Force × Distance
W = F × d
Hence,
Workdone = 15 × 10¹² Joules
HOPE IT HELPED ^_^
#brainly star
#follow me
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