Question

a car is has mass 1000kg is stopped in 10sec by applying breaks retardation due to breaks is 4/s2 then the retarding force is​

Answer 1

Answer:

15 m/s

Explanation:

Given :   m=1000 kg               u=10 m/s              t=10 s

Applied force        F=1000 N      (forwards)

Retarding force        f=500 N      (backwards)

Acceleration of the car in forward direction           a=  

m

F−f

​  

=  

1000

1000−500

​  

=0.5 m/s  

2

 

Using      v=u+at

∴   v=10+0.5×10=15 m/s