A Car is initially at rest starts moving with a uniform acceleration of 0.5m/s² and moves with it for 5 minutes find its velocity after 5 min and and distance Traveled in 5 mins .
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Answer :-
Given:
Initial velocity (u) = 0 m/s
Acceleration (a) = 0.5 m/s²
Time taken (t) = 5 min
Converting time taken to S.I units:
⟹ 5 × 60 sec
⟹ 300 sec
Using first equation of motion:
⟹ v = u + at
⟹ v = 0 + 0.5(300)
⟹ v = 0 + 150
⟹ v = 150 m/s
Using second equation of motion:
⟹ S = ut + 1/2 × at²
⟹ S = 0(300) + 1/2 × (0.5)(300)²
⟹ S = 0 + 1/2 × 0.5(90000)
⟹ S = 0 + 1/2 × 45000
⟹ S = 45000/2
⟹ S = 22500 m
or, 22500/1000 Km = 22.5 Km
∴,
⇒ Velocity after 5 min is 150 m/s.
⇒ Distance travelled in 5 min is 22.5 Km.
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