A car is initially moving with the speed of 30m\s . it comes to rest in 3 seconds after applying the brakes . calculate deceration , distance covered by car in 3 seconds .
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15
The deceleration would be -30/3 = -10m/sec^2
The distance traveled is
30(3)-5(9)
90-45
45
The distance traveled is
30(3)-5(9)
90-45
45
Answered by
3
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