A car is initially moving with the speed of 30m\s . it comes to rest in 3 seconds after applying the brakes . calculate deceration , distance covered by car in 3 seconds .
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u=30m/s
v=0m/s
t=3s
a) v=u+at
0=30+(a)3
-30/3=a
-10m/s^2
b). v^2 - u^2 = 2as
(0)^2 - (30)^2 = 2(-10)(s)
-900= -20s
-900/-20 =s
45m =s
v=0m/s
t=3s
a) v=u+at
0=30+(a)3
-30/3=a
-10m/s^2
b). v^2 - u^2 = 2as
(0)^2 - (30)^2 = 2(-10)(s)
-900= -20s
-900/-20 =s
45m =s
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Answered by
0
t=3sec
u=30m/s
v=0
a=?
s=?
a=v-u/t
a=0-30/3
a=-30/3
a=-10m/s^2
s=ut+1/2at^2
s= 30×3+1/2×-10×3
s=90-15
s=75m
u=30m/s
v=0
a=?
s=?
a=v-u/t
a=0-30/3
a=-30/3
a=-10m/s^2
s=ut+1/2at^2
s= 30×3+1/2×-10×3
s=90-15
s=75m
please mark it as brainlist
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