A car is moving along a circular road at a speed of 20 m/s. The radius of circular road is 10 m. If the speed is increased at the rate of 30 m/s2,what is the resultant acceleration at that moment?
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Some previous answers object to the problem being impossible in the real world. It is true that Physics problems usually assign values to the given data that are reasonable. But I had a math problem once that the teacher had not worked out before the test. It required simultaneous equations to solve it. It was workable, but it concluded that group that took the helicopter just flew around for 15 minutes and landed back at the original location while the distance that the group that “went by car” traveled was actually zero. In his honor, I will work with your data.
I have reviewed your 2 pages of work on the problem. It appears that you interpret the problem such that in one second, the car’s tangential speed increased from 20 m/s to 30 m/s. That is an increase of 10 m/s. Therefore the tangential acceleration, a_t, would be 10 m/s^2. (Because acceleration is change in velocity/time.)
Therefore your calculation of the resultant acceleration should be
a = sqrt(20^2 + 10^2) = sqrt(400 + 100) = sqrt(500) = 22.4 m/s^2
ʜᴏᴘᴇ ɪᴛs ʜᴇʟᴘs
I have reviewed your 2 pages of work on the problem. It appears that you interpret the problem such that in one second, the car’s tangential speed increased from 20 m/s to 30 m/s. That is an increase of 10 m/s. Therefore the tangential acceleration, a_t, would be 10 m/s^2. (Because acceleration is change in velocity/time.)
Therefore your calculation of the resultant acceleration should be
a = sqrt(20^2 + 10^2) = sqrt(400 + 100) = sqrt(500) = 22.4 m/s^2
ʜᴏᴘᴇ ɪᴛs ʜᴇʟᴘs
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Answer:
50m/s sq.
Explanation:
https://www.sarthaks.com/?qa=blob&qa_blobid=15706854115323235647
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