Question

A car is moving along a straight line. It moves from o to p in 18 seconds and returns from p to q in 6 seconds. Find it's average velocity and average speed from o to p and o to p back to q

Answer 1

for first
$360 \div 18$
for second
$720 \div 24$

Answer 2

Answer :

The Question is incomplete ! It should contain the diagram I have attached.

Given -

• The car is moving from O to P
• The time taken = 18 s
• The car then moves from P to Q
• The time taken = 6 s

To Find -

• Average velocity and Average speed

(a) From O to P and (B) From O to P and back to Q ?

Solution -

Average Velocity = Displacement/Time

Average Speed = Distance/Time

(a) The displacement between O and P = +360 m

The path travelled from O to P = 360 m

So, Average Velocity = +360/18 = +20 m/s

And, Average Speed = 360/18 = 20 m/s

(b) The displacement between O and Q = +240 m

The path travelled from O to P and back to Q = 360 + 120 = 480 m

Total time taken to travel from O to O and back to Q = 18 + 6 = 24 s

So, Average Velocity = +240/24 = +10 m/s

And, Average Speed = 480/24 = 20 m/s