Question

A car is moving along a straight road with
uniform acceleration. It passes through two
points P and Q separated by a distance with
velocities 30 kmh-1 and 40 kmh-1 respectively.
The velocity of the car midway between P and
Q is,
(1) 33.3 kmh-1
(2) 35 kmh-1
(3) 25.25 kmh-1
(4) 35.35 kmh-1​

Answer 1

Answer:

Assume acceleration of the car is a.

PQ=s

Using, v

2

=u

2

+2as.

=>40

2

=30

2

+2as

=>2as=700=>as=350

Now, assume velocity of car at a midpoint of PQ is V.

V

2

=vp

2

+2a(

2

s

)

=>V

2

=900+350=1250

=>V=35.35

s

m