Question

A car is moving at a speed of 18km/h. It start sretarding uniformly at1m/s² and
come storest. Find the distance travelled.​

Answer 1

Solution:-

Solution:-It's given that,

Solution:-It's given that,Initial velocity=18km/h

Solution:-It's given that,Initial velocity=18km/hTo convert it into m/s we will multiple it with 5/18.

Solution:-It's given that,Initial velocity=18km/hTo convert it into m/s we will multiple it with 5/18. = > 18 \times \frac{5}{18} \\ = > 5m \: per \: second

Solution:-It's given that,Initial velocity=18km/hTo convert it into m/s we will multiple it with 5/18. = > 18 \times \frac{5}{18} \\ = > 5m \: per \: secondSo,

Solution:-It's given that,Initial velocity=18km/hTo convert it into m/s we will multiple it with 5/18. = > 18 \times \frac{5}{18} \\ = > 5m \: per \: secondSo,Initial velocity=5m/s

Solution:-It's given that,Initial velocity=18km/hTo convert it into m/s we will multiple it with 5/18. = > 18 \times \frac{5}{18} \\ = > 5m \: per \: secondSo,Initial velocity=5m/sFinal velocity=0

Solution:-It's given that,Initial velocity=18km/hTo convert it into m/s we will multiple it with 5/18. = > 18 \times \frac{5}{18} \\ = > 5m \: per \: secondSo,Initial velocity=5m/sFinal velocity=0Acceleration= -1m/s^2

Solution:-It's given that,Initial velocity=18km/hTo convert it into m/s we will multiple it with 5/18. = > 18 \times \frac{5}{18} \\ = > 5m \: per \: secondSo,Initial velocity=5m/sFinal velocity=0Acceleration= -1m/s^2Time=?

Solution:-It's given that,Initial velocity=18km/hTo convert it into m/s we will multiple it with 5/18. = > 18 \times \frac{5}{18} \\ = > 5m \: per \: secondSo,Initial velocity=5m/sFinal velocity=0Acceleration= -1m/s^2Time=?By using equation,(I.e.)

Solution:-It's given that,Initial velocity=18km/hTo convert it into m/s we will multiple it with 5/18. = > 18 \times \frac{5}{18} \\ = > 5m \: per \: secondSo,Initial velocity=5m/sFinal velocity=0Acceleration= -1m/s^2Time=?By using equation,(I.e.)v=u+at

Solution:-It's given that,Initial velocity=18km/hTo convert it into m/s we will multiple it with 5/18. = > 18 \times \frac{5}{18} \\ = > 5m \: per \: secondSo,Initial velocity=5m/sFinal velocity=0Acceleration= -1m/s^2Time=?By using equation,(I.e.)v=u+at0 = 5 + ( - 1) \times t \\ 0 = 5 - t \\ t = 5

Solution:-It's given that,Initial velocity=18km/hTo convert it into m/s we will multiple it with 5/18. = > 18 \times \frac{5}{18} \\ = > 5m \: per \: secondSo,Initial velocity=5m/sFinal velocity=0Acceleration= -1m/s^2Time=?By using equation,(I.e.)v=u+at0 = 5 + ( - 1) \times t \\ 0 = 5 - t \\ t = 5So,

Solution:-It's given that,Initial velocity=18km/hTo convert it into m/s we will multiple it with 5/18. = > 18 \times \frac{5}{18} \\ = > 5m \: per \: secondSo,Initial velocity=5m/sFinal velocity=0Acceleration= -1m/s^2Time=?By using equation,(I.e.)v=u+at0 = 5 + ( - 1) \times t \\ 0 = 5 - t \\ t = 5So,time=5 second

Solution:-It's given that,Initial velocity=18km/hTo convert it into m/s we will multiple it with 5/18. = > 18 \times \frac{5}{18} \\ = > 5m \: per \: secondSo,Initial velocity=5m/sFinal velocity=0Acceleration= -1m/s^2Time=?By using equation,(I.e.)v=u+at0 = 5 + ( - 1) \times t \\ 0 = 5 - t \\ t = 5So,time=5 secondNow,

Solution:-It's given that,Initial velocity=18km/hTo convert it into m/s we will multiple it with 5/18. = > 18 \times \frac{5}{18} \\ = > 5m \: per \: secondSo,Initial velocity=5m/sFinal velocity=0Acceleration= -1m/s^2Time=?By using equation,(I.e.)v=u+at0 = 5 + ( - 1) \times t \\ 0 = 5 - t \\ t = 5So,time=5 secondNow,we will find the distance by using equation:-

Solution:-It's given that,Initial velocity=18km/hTo convert it into m/s we will multiple it with 5/18. = > 18 \times \frac{5}{18} \\ = > 5m \: per \: secondSo,Initial velocity=5m/sFinal velocity=0Acceleration= -1m/s^2Time=?By using equation,(I.e.)v=u+at0 = 5 + ( - 1) \times t \\ 0 = 5 - t \\ t = 5So,time=5 secondNow,we will find the distance by using equation:-s = ut + \frac{1}{2 } {at}^{2} \\ s = 5 \times 5 + \frac{1}{2} \times ( - 1) \times 25 \\ s = 25 - \frac{25}{2}

Solution:-It's given that,Initial velocity=18km/hTo convert it into m/s we will multiple it with 5/18. = > 18 \times \frac{5}{18} \\ = > 5m \: per \: secondSo,Initial velocity=5m/sFinal velocity=0Acceleration= -1m/s^2Time=?By using equation,(I.e.)v=u+at0 = 5 + ( - 1) \times t \\ 0 = 5 - t \\ t = 5So,time=5 secondNow,we will find the distance by using equation:-s = ut + \frac{1}{2 } {at}^{2} \\ s = 5 \times 5 + \frac{1}{2} \times ( - 1) \times 25 \\ s = 25 - \frac{25}{2} s = \frac{50 - 25}{2} \\ s = \frac{25}{2} \\ s = 12.5m

Solution:-It's given that,Initial velocity=18km/hTo convert it into m/s we will multiple it with 5/18. = > 18 \times \frac{5}{18} \\ = > 5m \: per \: secondSo,Initial velocity=5m/sFinal velocity=0Acceleration= -1m/s^2Time=?By using equation,(I.e.)v=u+at0 = 5 + ( - 1) \times t \\ 0 = 5 - t \\ t = 5So,time=5 secondNow,we will find the distance by using equation:-s = ut + \frac{1}{2 } {at}^{2} \\ s = 5 \times 5 + \frac{1}{2} \times ( - 1) \times 25 \\ s = 25 - \frac{25}{2} s = \frac{50 - 25}{2} \\ s = \frac{25}{2} \\ s = 12.5mHence,he travelled 12.5meters.