Question

a car is moving at a speed of 40 m/s on a circular track of radius 400m this speed.This increasing at the rate of 3m/s^2 acceleration of car is??

Answer 1

hope it helps u.!!..........

Answer 2

Hey Friend,

◆ Answer -
a = 5 m/s^2

◆ Explaination-
# Given-
r = 400 m
v = 40 m/s
at = 3 m/s^2

# Solution-
In circular motion, inear acceleration has two components - tangential & centripetal.

Tangential acceleration is -
at = 3 m/s^2

Centripetal acceleration is -
ac = v^2 / r
ac = (40)^2 / 400
ac = 4 m/s^2

Magnitude of linear acceleration is-
a = √(at^2 + ac^2)
a = √(3^2 + 4^2)
a = √(25)
a = 5 m/s^2

Therefore, linear acceleration of car is 5 m/s^2.

Hope this helps...