A car is moving at a speed of 90 km and another car at 36km and is 300m behind the first car. If the second car accelerates at 2 m /s and first at 1m/s.after how much time and distance the second car will catch up the first car
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Explanation:
Let us assume that the car A and B meet after a time
′
t
′
Distance travelled by A in that time is vt
=15t
Distance travelled by B is
s=ut+
2
1
at
2
s=
2
3t
2
2
3t
2
=15t
t=0,10s
t=0 is trivial . Therefore, at t=10s, both the cars meet.
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