Question

A car is moving at a speed of 90 km and another car at 36km and is 300m behind the first car. If the second car accelerates at 2 m /s and first at 1m/s.after how much time and distance the second car will catch up the first car

Answer 1

Explanation:

Let us assume that the car A and B meet after a time

′

t

′

Distance travelled by A in that time is vt

=15t

Distance travelled by B is

s=ut+

2

1

at

2

s=

2

3t

2

2

3t

2

=15t

t=0,10s

t=0 is trivial . Therefore, at t=10s, both the cars meet.

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