Physics, asked by maduecil, 11 months ago

A car is moving at a velocity of 36kmph. after 10 sec the velocity becomes 54kmph. find out acceleration .​

Answers

Answered by sudhanshushrma8
5

Answer:

0.5m/s*2

Explanation:

v1=36km/hr = 36*5/18=10m/s

v2=54km/h = 54*5/18=15m/s

t1=0s

t2=10s

therefore,

acceleration=v2-v1/t2-t1

=15-10/10-0

=5/10

=0.5m/s*2

Answered by latagupta789
2

Answer:

0.5m/ s* 2

Explanation:

V1 = 36km/ hr = 36*5/18=10m/s

V2= 54km/h= 54*5/18=15m/s

T1= 0s

T2= 10s

Therefore,

Accceleration, v2- v1/t2-t1

= 15-10/10-0

=5/10

=0.5m/s*2

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