A car is moving at a velocity of 72 km per HR. Suddenly breaks are applied so as to stop the car after 10 m. Find the force exerted by the brakes of the car. (if the total mass of the passengers and car is equal to 800 kg)
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72 kmph = 72 × 5/18 m/s = 20 m/s
a = u^2 / (2S)
= (20)^2 / (2 × 10)
= 20 m/s^2
F = ma
= 800kg × 20m/s^2
= 16000 N
= 16 kN
Force exerted by brakes on car is 16 kN
a = u^2 / (2S)
= (20)^2 / (2 × 10)
= 20 m/s^2
F = ma
= 800kg × 20m/s^2
= 16000 N
= 16 kN
Force exerted by brakes on car is 16 kN
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