A car is moving at an average speed of 202/5kmph. How much distance will it cover in 15/2 hrs?
Answers
Answered by
4
Hi.
Here is your answer-----------
Given-----
Time(t) = 15/2 hrs.
= 7.5 hrs.
Average speed (v) = 202/5 km/hr.
Using Formula,
v = d/t
d = v x t
d = (202/5) x 7.5
d = 303 km
Thus, distance is 303 km.
Hope it helps.
Have a nice day.
Here is your answer-----------
Given-----
Time(t) = 15/2 hrs.
= 7.5 hrs.
Average speed (v) = 202/5 km/hr.
Using Formula,
v = d/t
d = v x t
d = (202/5) x 7.5
d = 303 km
Thus, distance is 303 km.
Hope it helps.
Have a nice day.
satish66:
ok
Answered by
1
covering distance= velocity*time
= 202/5*(15/2)
=303 km
= 202/5*(15/2)
=303 km
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