A car is moving at the rate of 60 km per hour covers the distance in 15 minutes how long would it take to cover the same distance if the speed is reduced to
i.36 km per hour
ii. by 36 km
answer fast..
Answers
Answered by
1
Speed V = 60 kmph
Time = t = 15 min = 15/60 =1/4 hr
Distance covered = D = V * t = 15 km
1) New speed = 36 kmph
New duration to cover D : 15/36 hrs = 5/12 hr = 25 minutes
2) New speed = 60 - 36 = 24 kmph
New duration = 15/24 = 5/8 hr = 5*60/8 min = 37.5 min
Time = t = 15 min = 15/60 =1/4 hr
Distance covered = D = V * t = 15 km
1) New speed = 36 kmph
New duration to cover D : 15/36 hrs = 5/12 hr = 25 minutes
2) New speed = 60 - 36 = 24 kmph
New duration = 15/24 = 5/8 hr = 5*60/8 min = 37.5 min
kvnmurty:
:-)
Answered by
2
Hey!
Given,
Speed(v) = 60 kmph
Time (t) = 15 min or 1/4 hr
We know,
Distance(d) = speed(v) x time(t)
= 60 x 1/4
= 15 km
(i)Given, speed 36 kmph
Then, Time = distance/speed
= 15/36 hr or 5 minutes
(ii)Here speed will be!
= 60 - 36 = 24 kmph
Then time = distance/speed
= 15/24
= 5/8 hr or 37.5 min
Hope It Helps You!
Given,
Speed(v) = 60 kmph
Time (t) = 15 min or 1/4 hr
We know,
Distance(d) = speed(v) x time(t)
= 60 x 1/4
= 15 km
(i)Given, speed 36 kmph
Then, Time = distance/speed
= 15/36 hr or 5 minutes
(ii)Here speed will be!
= 60 - 36 = 24 kmph
Then time = distance/speed
= 15/24
= 5/8 hr or 37.5 min
Hope It Helps You!
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