Question

a car is moving in a horizontal level circular track with uniform speed V if R is the radius of circular path then the minimum coefficient of friction to avoid overturning is

Answer 1

For safe driving,
Friction force should be equal to centripetal Force

μmg = mV² / R
Divide both sides by m
μg = V² / R
μ = V² / (Rg)

∴ Minimum coefficient of friction required is equal to V² / (Rg)

Answer 2

Answer: ц = V²/ (Rg)

Explanation: For safe driving,

Friction force should be equal to centripetal Force

μmg = mV² / R

Divide both sides by m

μg = V² / R

μ = V² / (Rg)