A car is moving on a straight highway with speed of 252km/hr. It is brought to stop within a distance of 400m. What is the retardation of car and how long does it take for the car to stop?
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Answer:
u=126 km/h=126×
18
5
m/s=35m/s
v=0
s=200m
Newton's Equation of motion
v
2
−u
2
=2as
0
2
−35
2
=2a(200)
a=−3.0625m/s
2
Also
v=u+at
0=35−3.06t
t=11.4s
Explanation:
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