a car is moving on a straight road accelerates from a speed of 4.1 m/s to a speed of 6.9 m/s in 5.0 s what was its average acceleration
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Initial velocity,u=4.1m/s
Final velocity ,v=6.9m/s
Time taken=5.0secs
We know, acceleration=(v-u)/t where t=time.
Therefore, acceleration=(6.9-4.1)/5 m/sec square
=2.8/5 m/sec square
=0.56 m/sec square(ANS)
Final velocity ,v=6.9m/s
Time taken=5.0secs
We know, acceleration=(v-u)/t where t=time.
Therefore, acceleration=(6.9-4.1)/5 m/sec square
=2.8/5 m/sec square
=0.56 m/sec square(ANS)
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