Question

Find three numbers in ap whose sum and product is 36 and 1620

Answer 1

Let the three numbers in A.P be (a-d), a and (a+d) respectively

Sum of three numbers is 36

a-d+a+a+d=36

3a=36

a=12

Product of three numbers is 1620

(a-d)*a *(a+d) =1620

a(a²-d²)=1620

12(144-d²)=1620

144-d²=1620/12

144-135=d²

d²=9d=3

Therefore three numbers in A.P are (12-3),12,(12+3)
⇒9,12,15

Answer 2

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