Question

A car is moving with a speed of 36km/h .Its stopped in 10 sec. after applying brakes.Calculate the acceleration of the car.​

Answer 1

Answer:

-1m/s

Explanation:

Given,

A car is moving with a speed of 36km/h.

It's stops in 10sec after applying brakes.

Calculate the acceleration of the car.

We have,

• velocity of the car = 36km/h

Conversion in m/s :-

= 36 ÷ 3.6

= 10m/s

Acceleration of the car is given by,

$\bullet \: \: \boldsymbol {a = \dfrac{v - u}{t} }$

Where,

• $a$ denotes the acceleration.
• $v$ is the final velocity = 0 [Since it comes to rest]
• $u$ is the initial velocity = 10m/s
• $t$ is the time taken.

Substitute the given values,

$\implies \: a = \dfrac{0 - 10}{10}$

$\implies \: a = \dfrac{ - 10}{10}$

$\implies \: a = - 1\rm m \: s^{-1}$

∴ Acceleration of the car is -1m/s

__________________________

NOTE:

• Negative sign denotes the retardation.
• Acceleration = $\dfrac{\Delta v}{\Delta t}$

CONVERSION:

From km/h to m/s:-

• Divide the unit by 3.6

From m/s to km/h:-

• Multiply the unit by 3.6

Answer 2

$\huge\colorbox{lavender}{Question:}$

A car is moving with a speed of 36km/h .Its stopped in 10 sec. after applying brakes.Calculate the acceleration of the car.

Answer:

-1m/s

Explanation:

Given,

A car is moving with a speed of 36km/h.

A car is moving with a speed of 36km/h.It's stops in 10sec after applying brakes.

I hope it helps you!!!

have a Bangtan Day!!^^