One end of latusrectum of the parabola is
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Given equation is y2−4x−2y−3=0
⇒( −2y)=4x+3
⇒ −1=4x+3
⇒ =4(x+1)
Shift the origin to (−1,1)
⇒ =4X
Here focus is at (1,0).
Hence, focus of original parabola becomes
(1−1,0+1)=(0,1)
Therefore, equation of latusrectum is x=0.
Thus,
Point of intersection of parabola and latus rectum is,
−2y−3=0
⇒ y = −1 or 3
So, the required points are (0,−1),(0,3).
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