a car is moving with a speed of 60km/hr.Suddenly the barkes are applied and the car is brought to rest at 10 sec.Calculate the retardation
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Answered by
1
here let retardation be a and
initial velocity = 60km/hr=>60*5/18=>16.66m/s
final velocity => 0 and time=> 10sec
therefore v= u+at
=> -16.66=10a => a = -1.66m/s^2
initial velocity = 60km/hr=>60*5/18=>16.66m/s
final velocity => 0 and time=> 10sec
therefore v= u+at
=> -16.66=10a => a = -1.66m/s^2
Answered by
1
initial speed is 60km/hr
u=60km/Hr=16.67m/sec
final speed v=0
time 10sec =1/360
v=u+at
-16.67/10=a
1.67
retardation =1.67ms^-2
u=60km/Hr=16.67m/sec
final speed v=0
time 10sec =1/360
v=u+at
-16.67/10=a
1.67
retardation =1.67ms^-2
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