A car is moving with a uniform velocity of 10m/s. the driver of the car decides to overtake the bus moving ahead of the car. So the driver of the car accelerates at 1m/s2 for 10 sec. Find the velocity of the car at the end of 10 sec. also find the distance traveled by the car while accelerating
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u = 10 m/sec
a = 1 m/sec²
t = 10 secs
final velocity = v = ?
v = at + u
= (1 m/.sec² × 10 sec) + 10 m/sec
= 10 m/s + 10 m/sec
= 20 m/sec
so, final velocity = 20 m/sec
now, for calculating distance traveled by the car during accelerating :-
u = 10 m/sec
t = 10 sec
a = 1 m/sec²
distance traveled = ut + 1/2 × at²
= 10 × 10 + 1/2 × 1 × 100
= 100 + 50
= 150 m
so, distance traveled during accelerating is 150 m.
a = 1 m/sec²
t = 10 secs
final velocity = v = ?
v = at + u
= (1 m/.sec² × 10 sec) + 10 m/sec
= 10 m/s + 10 m/sec
= 20 m/sec
so, final velocity = 20 m/sec
now, for calculating distance traveled by the car during accelerating :-
u = 10 m/sec
t = 10 sec
a = 1 m/sec²
distance traveled = ut + 1/2 × at²
= 10 × 10 + 1/2 × 1 × 100
= 100 + 50
= 150 m
so, distance traveled during accelerating is 150 m.
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Explanation:
A car is moving with a uniform velocity of 10m/s. the driver of the car decides to overtake the bus moving ahead of the car. So the driver of the car accelerates at 1m/s2 for 10 sec. Find the velocity of the car at the end of 10 sec. also find the distance traveled by the car while accelerating
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