Question

A car is moving with a velocity of 63 km/hr and
its acceleration is 10m/sec2
. Find the distance
it will cover in the 5th second of its motion​

Answer 1

Answer:

62.5 metres

Step-by-step explanation:

Given :

• Initial velocity = u = 63 km/hr = 63×5/18 = 17.5 m/s

• Acceleration = a = 10 m/s²

To find :

• Distance travelled in the 5th second by the car

Distance travelled in nth second = u + a/2 (2n-1)

Distance travelled in the 5th second = 17.5 + 10/2 ( 2×5 - 1)

Distance travelled in the 5th second = 17.5 + 5(9)

Distance travelled in the 5th second = 17.5+45

Distance travelled in the 5th second = 62.5 metres

The distance travelled in the 5th second of motion is equal to 62.5 metres

More :

• First equation of motion = v = u+at

• Second equation of motion = s = ut+½at²

• Third equation of motion = v²-u²=2as